Accessing Inherited Functions Hackerrank Solution in C++

You are given three classes A, B and C. All three classes implement their own version of func. In class A, func multiplies the value passed as a parameter by 2: Accessing Inherited Functions Hackerrank Solution in C++.

class A

{

public:

A(){

callA = 0;

}

private:

int callA;

void inc(){

callA++;

}

protected:

void func(int & a)

{

a = a * 2;

inc();

}

public:

int getA(){

return callA;

}

};

In class B, func multiplies the value passed as a parameter by 3:

class B

{

public:

B(){

callB = 0;

}

private:

int callB;

void inc(){

callB++;

}

protected:

void func(int & a)

{

a = a * 3;

inc();

}

public:

int getB(){

return callB;

}

};

In class C, func multiplies the value passed as a parameter by 5:

class C

{

public:

C(){

callC = 0;

}

private:

int callC;

void inc(){

callC++;

}

protected:

void func(int & a)

{

a = a * 5;

inc();

}

public:

int getC(){

return callC;

}

};

You are given a class D:

class D

{

int val;

public:

//Initially val is 1

D()

{

val = 1;

}

//Implement this function

void update_val(int new_val)

{

}

//For Checking Purpose

void check(int); //Do not delete this line.

};

You need to modify the class D and implement the function update_val which sets D's val to new_val by manipulating the value by only calling the func defined in classes A, B and C.

It is guaranteed that new_val has only 2, 3 and 5 as its prime factors.

Input Format

Implement class D's function update_val. This function should update D's val only by calling A, B and C's func.

Constraints

1 <= new_val <= 10000

Note: The new_val only has 2, 3 and 5 as its prime factors.

Sample Input

new_val = 30

Sample Output

A's func will be called once.

B's func will be called once.

C's func will be called once.

Explanation

Initially, val = 1.

A's func is called once:

val = val*2

val = 2

B's func is called once:

val = val*3

val = 6

C's func is called once:

val = val*5

val = 30

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Accessing Inherited Functions Hackerrank Solution in C++

#include <iostream>
using namespace std;

int callA = 0;
int callB = 0;
int callC = 0;
class A
{
	protected:

		void func(int & a)
		{
			a = a * 2;
			callA++;
		}
};

class B
{
	protected:
		void func(int & a)
		{
			a = a * 3;
			callB++;
		}
};

class C
{
	protected:
		void func(int & a)
		{
			a = a * 5;
			callC++;
		}
};

class D: public A, public B, public C
{
	int val;
	public:
		//Initially val is 1
		D()
		{
			val = 1;
		}

	//Implement this function
	void update_val(int new_val)
	{
		int a = new_val;
		while (a % 2 == 0)
		{
			a = a / 2;
			A::func(val);
		}

		while (a % 3 == 0)
		{
			a = a / 3;
			B::func(val);
		}

		while (a % 5 == 0)
		{
			a = a / 5;
			C::func(val);
		}
	}

	//For Checking Purpose
	void check(int);	//Do not delete this line.
};

void D::check(int new_val)
{
	update_val(new_val);
	cout << "Value = " << val << endl << "A's func called " << callA << " times " << endl << "B's func called " << callB << " times " << endl << "C's func called " << callC << " times" << endl;
}

int main()
{
	D d;
	int new_val;
	cin >> new_val;
	d.check(new_val);

}