Day 5 Loops Hackerrank Solution in C

We have to find the Day 5 Loops Hackerrank Solution in C programming language. This is a part of the 30 days of code hackerrank programming challenge. So we are going to solve this programming challenge with full logic, code explanations, and syntax. Before going to the actual programming challenge, let's find out what we have and what we have to do to solve the hackerrank day 5 solution in c programming or Hackerrank Loops Solution, and another programming as well.

So we have the following day 5 loops hackerrank programming challenge.

Objective

In this challenge, we're going to use loops to help us do some simple math. Get the Hackerrank Day 5 Solution in C programming.

Task

Given an integer,n, print its first 10 multiples. Each multiple n*i (where 1<=i<=10) should be printed on a new line in the form: n x i = result.

Input Format

A single integer,n.

Constraints

2<=n<=20

Output Format

Print 10 lines of output; each line i (where 1<=i<=10) contains the results of n*i in the form: n x i = result.

Sample Input

Sample Output

2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
2 x 10 = 20

You can practice and submit your loops hackerrank solution by clicking on this link: Click Here

Day 5 Loops Hackerrank Solution in C

#include <assert.h>

#include <limits.h>

#include <math.h>

#include <stdbool.h>

#include <stddef.h>

#include <stdint.h>

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

char * readline();

int main() {
  char * n_endptr;
  char * n_str = readline();
  int n = strtol(n_str, & n_endptr, 10);

  if (n_endptr == n_str || * n_endptr != '\0') {
    exit(EXIT_FAILURE);
  }

  for (int i = 1; i <= 10; i++) {
    printf("%i x %i = %i\n", n, i, n * i);
  }
  return 0;
}

char * readline() {
  size_t alloc_length = 1024;
  size_t data_length = 0;
  char * data = malloc(alloc_length);

  while (true) {
    char * cursor = data + data_length;
    char * line = fgets(cursor, alloc_length - data_length, stdin);

    if (!line) {
      break;
    }

    data_length += strlen(cursor);

    if (data_length < alloc_length - 1 || data[data_length - 1] == '\n') {
      break;
    }

    size_t new_length = alloc_length << 1;
    data = realloc(data, new_length);

    if (!data) {
      break;
    }

    alloc_length = new_length;
  }

  if (data[data_length - 1] == '\n') {
    data[data_length - 1] = '\0';
  }

  data = realloc(data, data_length);

  return data;
}

Day 5 For Loop in C Hackerrank Solution Logic

Day 5 FOR Loop in C Hackerrank Solution Logic, We can take a FOR Loop and put the condition in the loop to print the table. This is a straightforward program. We need to use only one FOR Loop for this problem. This programming can be solved using the 'While Loop' or 'While Do Loop' and 'Do-While Loop.' So why wait, let's find out Hackerrank Day 5 Solution in C programming language.

Try to solve this problem using the 'While Loop' and 'Do-While Loop.' So according to the above syntax take a user input, initialize the loop with i = 0 and put the condition i <= 10 and the last condition is i++ or i =i+1. And multiplication i and n and printing the result according to the programming challenge statement.

Explanation of Loops Hackerrank Solution

n is an integer number we have to print the table of n, first take user input and store the value in 'n'. after that use a 'for loop' and put the three conditions in 'for loop'. Below is a for-loop syntax.

For Loop Syntax

for(initialization ; condition ; increament / decreament)
{
---
---
Executable statements
---
---
}

The Output of Number 10.

This will print the table of any number let's take an example of number 10(10 is our input for this Hackerrank Loops Solution) then the output is below.


10 x 1 = 10
10 x 2 = 20
10 x 3 = 30
10 x 4 = 40
10 x 5 = 50
10 x 6 = 60
10 x 7 = 70
10 x 8 = 80
10 x 9 = 90
10 x 10 = 100

If you want to solution of 30 days of code solution(All solutions from day 0 to day 29, including day 5 loops hackerrank solution) from Day 0 please check the 30 Days of code solutions. You can also find more programs below in this post.