Geeksforgeeks Solution For " Square Divisors "

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Problem :- Given a number N.Your task is to print the no of divisors of number N which are perfect squares.

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Solution :- 

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int t;
cin>>t;
    while(t--)
    {
    int i,j,res=0;
    unsigned long long int n;
    
    cin>>n;
        for(j=1;j*j<=n;j++)
        {
            if(n%(j*j) == 0)
            {
                res++;
            }
        }
        cout<<res<<endl;
    }
    return 0;
}

Output:-