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Problem :- Given a positive integer N, print count of set bits in it. For example, if the given number is 6, output should be 2 as there are two set bits in it.
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Solution :-
#include <bits/stdc++.h>
using namespace std;
int main()
{
int t;
cin>>t;
while(t--)
{
int n,i,j,tmp=0;
cin>>n;
while(n!=0)
{
i=n%2;
if(i==1)
{
tmp++;
}
n=n/2;
}
cout<<tmp<<endl;
}
return 0;
}
Output:-
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