Geeksforgeeks Solution For " Roots of Quadratic Equation "

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Problem :- Given a quadratic equation in the form ax2 + bx + c, find floor of roots of it.  For example floor of 5.6 is 5.

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Solution :-

#include <iostream>
#include <cmath>
using namespace std;
int main() 
{
    int t;
    cin>>t;
    while(t--)
    {
    double a, b, c, d, root1,root2, realPart, imaginaryPart;
    cin>>a>>b>>c;
    d = b*b-4*a*c;
    if (d > 0)
    {
        root1 = (-b+sqrt(d))/(2*a);
        root2 = (-b-sqrt(d))/(2*a);
        cout<<floor(root1)<<" "<<floor(root2)<<endl;
    }
    else if (d == 0)
    {
        root1 = root2 = -b/(2*a);
        cout<<floor(root1)<<" "<<floor(root2)<<endl;    }
    else
    {
        cout<<"Imaginary"<<endl;
    }
    
    }
return 0;
}

Output:-