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Problem :- Given an unsigned integer, find it's parity. Parity of a number refers to whether it contains an odd or even number of 1-bits. The number has “odd parity”, if it contains odd number of 1-bits and is “even parity” if it contains even number of 1-bits.
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Solution :-
#include <iostream>
using namespace std;
int main()
{
int t;
cin>>t;
while(t--)
{
int n,even=0,odd=0,tmp=0;
cin>>n;
while(n>0)
{
if(n%2==1)
{
even++;
}
else
{
odd++;
}
n=n/2;
}
if(even%2==0)
cout<<"even\n";
else
cout<<"odd\n";
}
return 0;
}
Output:-
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