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Problem :- Given three distinct numbers, find the number with value in middle (Try to do it with minimum comparisons).
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Solution :-
#include <iostream>
using namespace std;
int main()
{
int t;
cin>>t;
while(t--)
{
long a,b,c;
cin>>a>>b>>c;
if ((a> b && a <c) || (a <b && a >c))
cout<<a;
else if ((b> a && b <c) || (b <a && b >c))
cout<<b;
else if ((c> a && c <b) || (c <a && c> b))
cout<<c;
}
return 0;
}
Output:-
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