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Problem :- Given a decimal number and the base to which it should be converted. Convert the given number to the given base.
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Solution :-
#include<bits/stdc++.h>
using namespace std;
char value(int num)
{
if(num>=0 && num <=9)
return char(num+'0');
else
return char(num-10+'A');
}
string from_decimal(string &s ,int base,int num)
{
while(num>0)
{
s.push_back(value(num%base));
num/=base;
}
reverse(s.begin(),s.end());
return s;
}
int main()
{
int t;
cin>>t;
while(t--)
{
int n,base;
cin>>base>>n;
string s="";
cout << from_decimal(s,base,n);
cout<<endl;
}
}
Output:-
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