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Problem :- Write a program to find the compund interest for given principal amount P , time T(in years), compounds N times in a year at rate R. Calculate floor of future value of given principal amount.
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Solution :-
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
int t1;
cin>>t1;
while(t1--)
{
double p=0,n=0,t=0,r=0,i=0,co=0,po=0;
cin>>p>>t>>n>>r;
i=(1+r/(n*100));
co=pow(i,n*t);
po=p*co;
cout<<floor(po)<<endl;
}
return 0;
}
Output:-
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