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Problem :- Given two positive numbers x and y, check if y is a power of x or not.
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Solution :-
#include <iostream>
#include<math.h>
using namespace std;
int main()
{
int t;
cin>>t;
while(t--)
{
int x,y,z=1,z1=0,i;
cin>>x>>y;
if(x==1 && y==1){
cout<<"1\n";
continue;
}
else if(x==1){
cout<<z1<<endl;
continue;
}
//break;
while(y%x==0)
y/=x;
if(y==1)
cout<<"1\n";
else
cout<<"0\n";
}
return 0;
}
Output:-
Sorry to say but this solutions are complicated to understand. And please try to present in more clean way it looks hectic.
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