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Problem :- Given coordinates of four points in a plane, find if the four points form a square or not.
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Solution :-
#include <iostream>
#include<math.h>
using namespace std;
int main()
{
int t,x1,x2,x3,x4,y1,y2,y3,y4;
double r,d1,d2,d3,d4,d5,d6;
r=sqrt(2);
cin>>t;
while(t--)
{
cin>>x1>>y1>>x2>>y2>>x3>>y3;
d1=sqrt(((x2-x1)*(x2-x1))+((y2-y1)*(y2-y1)));
d2=sqrt(((x3-x2)*(x3-x2))+((y3-y2)*(y3-y2)));
d3=sqrt(((x4-x3)*(x3-x3))+((y4-y3)*(y4-y3)));
d4=sqrt(((x1-x4)*(x1-x4))+((y1-y4)*(y1-y4)));
//d5 d6 are diagonal
d5=sqrt(((x3-x1)*(x3-x1))+((y3-y1)*(y3-y1)));
d6=sqrt(((x4-x2)*(x4-x2))+((y4-y2)*(y4-y2)));
if((d1==d2)&&(d2==d3)&&(d3==d4)&&(d4==d1)&&(d5==d6))
cout<<"1"<<endl;
else
cout<<"0"<<endl;
}
return 0;
}
Output:-
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