Problem :- C Program To Find Row In An Array That Include The Greatest Amount Of Even Number
Input Is Below
#include<iostream>
using namespace std;
int main()
{
int a[10][10],n,l,i,j,count=0;
cout<<"\nEnter The Matrix Size (l*l)\n";
cin>>l;
cout<<"\nEnter The Row Number Of Matrix\n";
cin>>n;
if(n<0||n<=l)
{
}
else
{
cout<<"\nRow Is Exceed The Limit Enter Value >0 And Less Than Size Of Matrix \n";
exit(0);
}
cout<<"Enter The Matrix Value\n";
for(i=1;i<=l;i++)
for(j=1;j<=l;j++)
cin>>a[i][j];
cout<<"\n\nMatrix Row Is Given Below\n\n";
for(i=1;i<=l;i++)
{
cout<<a[n][i]<<" ";
if(a[n][i]%2==0)
count++;
}
cout<<"\n\nNo. Of Even Number In Row IS = "<<count;
return 0;
}
Output:-
Input Is Below
Solution :-
using namespace std;
int main()
{
int a[10][10],n,l,i,j,count=0;
cout<<"\nEnter The Matrix Size (l*l)\n";
cin>>l;
cout<<"\nEnter The Row Number Of Matrix\n";
cin>>n;
if(n<0||n<=l)
{
}
else
{
cout<<"\nRow Is Exceed The Limit Enter Value >0 And Less Than Size Of Matrix \n";
exit(0);
}
cout<<"Enter The Matrix Value\n";
for(i=1;i<=l;i++)
for(j=1;j<=l;j++)
cin>>a[i][j];
cout<<"\n\nMatrix Row Is Given Below\n\n";
for(i=1;i<=l;i++)
{
cout<<a[n][i]<<" ";
if(a[n][i]%2==0)
count++;
}
cout<<"\n\nNo. Of Even Number In Row IS = "<<count;
return 0;
}
Output:-
number
ReplyDeleteamount - of uncountable
number - of countable
amount of sand/salt/flour
number of characters/flowers/numbers