Java Program to Reverse a Number Using While Loop

Problem:- Java Program to Reverse a Number, write a Java Program to Reverse a Number Using While Loop Ie. If a number is 12345 then it prints 54321.

Logic:- Logic for reverse a digit is simple lets take an example 12345 now first we divide a number with 10 so we get reminder 5 store the reminder and then and using this logic we multiply rev = rev * 10 + rem and again divide the number with 10 ,now number is 1234 and repeat a process again and again until number becomes greater or equal 1.Or you can try this problem with different -2 loop

Note:- Always remember Do Not try to print the reverse Digit always try to modify Like you can also solve the problem

while(n!=0)
{
rev=n%10;
System.out.print("Reversed Number = "+reverse);
n=n/10
}

but in this way number is printing actually not reversing. If you Understood then try to solve given a problem.


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Try Yourself- C Program to Check a Number is Palindrome or Not Using While Loop

Java Program to Reverse a Number Using While Loop

/*Program By Ghanendra Yadav
   Visit http://www.programmingwithbasics.com/
*/

import java.util.Scanner;

public class reverse
{
    public static void main(String args[])
    {
        int n, reverse=0, rem;
 Scanner sc = new Scanner(System.in);
 
        System.out.print("Enter The Number That You Want Reverse : \n\n");
        n = sc.nextInt();
 
 while(n!=0)
 {
 rem=n%10;
 reverse=reverse*10+rem;
 n/=10;
 }
 
 System.out.print("Reversed Number = "+reverse);
 
 }
}

Output:-

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