C Program to Count Number of Digits of a Number (Integer)

Problem:- Write A C Program to Count Number of Digits of a Number (Integer) Using While Loop.

Logic:- There are two methods for counting a number of digit in a number 

Method 1:- Using inbuilt Function

Example :- Number = 12345

Number_Of_Digit = log10(Number)+1

Number_Of_Digit = 5

Method 2:- Using Loop

while(n!=0)

{

  n/=10;          

      ++count;

}

Try Yourself C Program For Find A Grade Of Given Marks Using Switch Case

Solution:-

Method 1:-

#include<stdio.h>

int main()

{

  //Ghanendra Yadav

  int n,count=0;

  

  printf("Enter Any Number To Count Digit : \n\n");

  scanf("%d", &n);

  

  while(n!=0)

  {

      n/=10;          

      ++count;

  }

  printf("\nNumber of Digits Is = %d",count);

return 0;

}

Method 2:-

#include<stdio.h>

#include<math.h>

int main()

{

  //Ghanendra Yadav

  int n,count=0;

  

  printf("Enter Any Number To Count Digit : \n\n");

  scanf("%d", &n);

  

  count=log10(n)+1;

 

  printf("\nNumber of Digits Is = %d",count);

return 0;

}

Output:-

Method 1:-

Method 2:-