Problem :- Write A C++ Program To Display Size Of Different Datatype. Here one thing noted down size of Datatype maybe depend upon your Operating System . Operating System You Are using maybe 32 Bit Or 64 Bit
Logic :- For This Type of problem C++ Can Handle Easily .C++ have a "sizeof" Operator to find a size of any datatype Follow Given A Syntax
Syntax :- sizeof( datatype )
Replace Datatype by following datatype
int
float
double
long double
long long
There is another way to find the size of datatype by using pointer
See Also :- C Program To Display Size Of Different Datatype
Solution :-
#include<iostream>
#include<math.h>
using namespace std;
int main()
{
cout<<"size of int "<<sizeof(int)<<endl;
cout<<"size of float "<<sizeof(float)<<endl;
cout<<"size of double "<<sizeof(double)<<endl;
cout<<"size of long "<<sizeof(long)<<endl;
cout<<"size of long double "<<sizeof(long double)<<endl;
cout<<"size of long long int "<<sizeof(long long int)<<endl;
cout<<"size of long long "<<sizeof(long long)<<endl;
}
See Also :- Java Program To Display Size Of Different Datatype
Output :-
Logic :- For This Type of problem C++ Can Handle Easily .C++ have a "sizeof" Operator to find a size of any datatype Follow Given A Syntax
Syntax :- sizeof( datatype )
Replace Datatype by following datatype
int
float
double
long double
long long
There is another way to find the size of datatype by using pointer
See Also :- C Program To Display Size Of Different Datatype
Solution :-
#include<iostream>
#include<math.h>
using namespace std;
int main()
{
cout<<"size of int "<<sizeof(int)<<endl;
cout<<"size of float "<<sizeof(float)<<endl;
cout<<"size of double "<<sizeof(double)<<endl;
cout<<"size of long "<<sizeof(long)<<endl;
cout<<"size of long double "<<sizeof(long double)<<endl;
cout<<"size of long long int "<<sizeof(long long int)<<endl;
cout<<"size of long long "<<sizeof(long long)<<endl;
}
See Also :- Java Program To Display Size Of Different Datatype
Output :-
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