Problem :- Write A Program To Find Number Is Prime Or Not
Prime Number :- A Number That Can Only Divisible By Itself or 1.
You can see that it's clear a number divisible by itself or one then use a loop start from one like condition=1 and max condition up to <=Number
and divide a number by condition and increase counter by ++ if number divide after the end if count is equal to 2 then number is prime otherwise not.
Solution :-
#include<iostream>
using namespace std;
int main()
{
int number,count=0;
cout<<"ENTER NUMBER TO CHECK IT IS PRIME OR NOT ";
cin>>number;
for(int a=1;a<=number;a++)
{
if(number%a==0)
{
count++;
}
}
if(count==2)
{
cout<<"\n"<<number<<"IS PRIME NUMBER \n";
}
else
{
cout<<"\n"<<number<<"IS NOT A PRIME NUMBER \n";
}
return 0;
}
Output:-
Prime Number :- A Number That Can Only Divisible By Itself or 1.
You can see that it's clear a number divisible by itself or one then use a loop start from one like condition=1 and max condition up to <=Number
and divide a number by condition and increase counter by ++ if number divide after the end if count is equal to 2 then number is prime otherwise not.
Solution :-
#include<iostream>
using namespace std;
int main()
{
int number,count=0;
cout<<"ENTER NUMBER TO CHECK IT IS PRIME OR NOT ";
cin>>number;
for(int a=1;a<=number;a++)
{
if(number%a==0)
{
count++;
}
}
if(count==2)
{
cout<<"\n"<<number<<"IS PRIME NUMBER \n";
}
else
{
cout<<"\n"<<number<<"IS NOT A PRIME NUMBER \n";
}
return 0;
}
Output:-
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