Day 7 Arrays Hackerrank Solution in C & C++

Write a Program to Day 7 Arrays Hackerrank Solution in C and C++ with Complete Explanation. This is a very simple problem, here we need to only reverse the array and print the elements of the array. As we know the array index starts with zero to n-1. here we just reverse the array by first printing the array's last index and then the second last index like n, n-1, n-2,..................... up to (greater or equal) 0 (Zero).

Example: suppose an array with 5 elements is 10, 20, 30, 40, 50 and the index of the array is 0, 1, 2, 3, 4 so first print index 4 and element 50 then index 3 and element 40 and so on up to index 0 and element 10. Check the below picture its shows how exactly the array is printing the elements in reverse order.

All solutions provided here are in C++ (CPP). If you want these solutions in C, and Java comments below or send a mail with your query like " day n solution in C / C++ / Java. If you want 30 days solution (All previous solutions from day 0 ) from Day 0 please check the below link. You can also find more programs below in this post. Check the below solution with the full explanation (explanation in simple language).

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Hackerrank C++ Array Solution

#include <bits/stdc++.h>

using namespace std;

vector < string > split_string(string);

int main() {
  int n;
  cin >> n;
  cin.ignore(numeric_limits < streamsize > ::max(), '\n');

  string arr_temp_temp;
  getline(cin, arr_temp_temp);

  vector < string > arr_temp = split_string(arr_temp_temp);

  vector < int > arr(n);

  for (int i = 0; i < n; i++) {
    int arr_item = stoi(arr_temp[i]);

    arr[i] = arr_item;
  }

  for (int i = n - 1; i >= 0; i--) {
    cout << arr[i] << " ";
  }

  return 0;
}

vector < string > split_string(string input_string) {
  string::iterator new_end = unique(input_string.begin(), input_string.end(), [](const char & x,
    const char & y) {
    return x == y and x == ' ';
  });

  input_string.erase(new_end, input_string.end());

  while (input_string[input_string.length() - 1] == ' ') {
    input_string.pop_back();
  }

  vector < string > splits;
  char delimiter = ' ';

  size_t i = 0;
  size_t pos = input_string.find(delimiter);

  while (pos != string::npos) {
    splits.push_back(input_string.substr(i, pos - i));

    i = pos + 1;
    pos = input_string.find(delimiter, i);
  }

  splits.push_back(input_string.substr(i, min(pos, input_string.length()) - i + 1));

  return splits;
}

Day 7 Arrays Hackerrank Solution in C

#include <assert.h>
#include <limits.h>
#include <math.h>
#include <stdbool.h>
#include <stddef.h>
#include <stdint.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
 int size;
scanf("%d", &size);
int arr[size];
int m=0;
// Now while loop will read all the integers ignoring white spaces.
while(m<size && scanf("%d",&arr[m])==1)
    m++;

int x=0;
int y=size-1;
int temp;
//Exchanging or Swapping the first and last values and then second and 2nd last.so on
while(x<y)
{
    temp=arr[x];
    arr[x]=arr[y];
    arr[y]=temp;
    x++;
    y--;
}
//printing the  single space seperated array values.
for(int k=0;k<size;k++)
{
    printf("%d ", arr[k]);
}
return 0;
}