Geeksforgeeks Solution For " Reverse Coding "

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Problem :- Reverse Coding

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Solution :- 

#include <iostream>
using namespace std;

int main() {
int t;
cin>>t;
while(t--){
   int n,m;
   cin>>n>>m;
   int c=(n*(n+1))/2;
   if(c==m)
       cout<<1<<endl;
        else
            cout<<0<<endl;
}
return 0;
}

Output:-